t(t-2)+2(2t-1)=t^2+4

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Solution for t(t-2)+2(2t-1)=t^2+4 equation:


Simplifying
t(t + -2) + 2(2t + -1) = t2 + 4

Reorder the terms:
t(-2 + t) + 2(2t + -1) = t2 + 4
(-2 * t + t * t) + 2(2t + -1) = t2 + 4
(-2t + t2) + 2(2t + -1) = t2 + 4

Reorder the terms:
-2t + t2 + 2(-1 + 2t) = t2 + 4
-2t + t2 + (-1 * 2 + 2t * 2) = t2 + 4
-2t + t2 + (-2 + 4t) = t2 + 4

Reorder the terms:
-2 + -2t + 4t + t2 = t2 + 4

Combine like terms: -2t + 4t = 2t
-2 + 2t + t2 = t2 + 4

Reorder the terms:
-2 + 2t + t2 = 4 + t2

Add '-1t2' to each side of the equation.
-2 + 2t + t2 + -1t2 = 4 + t2 + -1t2

Combine like terms: t2 + -1t2 = 0
-2 + 2t + 0 = 4 + t2 + -1t2
-2 + 2t = 4 + t2 + -1t2

Combine like terms: t2 + -1t2 = 0
-2 + 2t = 4 + 0
-2 + 2t = 4

Solving
-2 + 2t = 4

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 2t = 4 + 2

Combine like terms: -2 + 2 = 0
0 + 2t = 4 + 2
2t = 4 + 2

Combine like terms: 4 + 2 = 6
2t = 6

Divide each side by '2'.
t = 3

Simplifying
t = 3

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